$argv
$argv — 传递给脚本的参数数组
说明
包含当运行于命令行下时传递给当前脚本的参数的数组。
注意: 第一个参数总是当前脚本的文件名,因此 $argv[0] 就是脚本文件名。
注意: 这个变量仅在 register_argc_argv 打开时可用。
警告
要测试脚本是否从命令行运行,应使用 php_sapi_name(),而不是检查是否设置了 $argv 或 $_SERVER['argv']。
示例
示例 #1 $argv 示例
<?php
var_dump($argv);
?>
当使用这个命令执行:php script.php arg1 arg2 arg3
以上示例的输出类似于:
array(4) { [0]=> string(10) "script.php" [1]=> string(4) "arg1" [2]=> string(4) "arg2" [3]=> string(4) "arg3" }
注释
注意:
也可以在 $_SERVER['argv'] 中获取。
+添加备注
用户贡献的备注 6 notes
tufan dot oezduman at googlemail dot com ¶
13 years ago
Please note that, $argv and $argc need to be declared global, while trying to access within a class method.
<?php
class A
{
public static function b()
{
var_dump($argv);
var_dump(isset($argv));
}
}
A::b();
?>
will output NULL bool(false) with a notice of "Undefined variable ..."
whereas global $argv fixes that.
hamboy75 at example dot com ¶
11 years ago
To use $_GET so you dont need to support both if it could be used from command line and from web browser.
foreach ($argv as $arg) {
$e=explode("=",$arg);
if(count($e)==2)
$_GET[$e[0]]=$e[1];
else
$_GET[$e[0]]=0;
}
vatruski at t dot me ¶
1 year ago
You can reinitialize the argument variables for web applications.
So if you created a command line, with some additional tweaks you can make it work on the web.
Steve Schmitt ¶
15 years ago
If you come from a shell scripting background, you might expect to find this topic under the heading "positional parameters".
php at simoneast dot net ¶
9 years ago
Sometimes $argv can be null, such as when "register-argc-argv" is set to false. In some cases I've found the variable is populated correctly when running "php-cli" instead of just "php" from the command line (or cron).
备份地址:http://www.lvesu.com/blog/php/reserved.variables.argv.php