ReflectionClass::implementsInterface

(PHP 5, PHP 7, PHP 8)

ReflectionClass::implementsInterface — 实现接口

说明

public ReflectionClass::implementsInterface(ReflectionClass|string $interface): bool

检查其是否实现了接口（interface）。

参数

interface: 接口（interface）的名称。

返回值

成功时返回 true，或者在失败时返回 false。

错误／异常

如果 interface 不是接口，则 ReflectionClass::implementsInterface() 会抛出 ReflectionException。

参见

ReflectionClass::isInterface() - 检查类是否是一个接口（interface）
ReflectionClass::isSubclassOf() - 检查是否为子类
interface_exists() - 检查接口是否已被定义
对象接口

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用户贡献的备注 3 notes

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jtunaley at gmail dot com ¶

6 years ago

Note that this method also returns true when the thing you're reflecting is the interface you're checking for:

<?php
interface MyInterface {}

$reflect = new ReflectionClass('MyInterface');
var_dump($reflect->implementsInterface('MyInterface')); // bool(true)
?>

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dhairya dot coder at gmail dot com ¶

9 years ago

//checks that whether class Fruit implements interface apple or not 

interface Apple {

    function taste();
}

class Fruit implements Apple {

    function taste() {
        echo "Seet";
    }
}

$obj=new ReflectionClass('Fruit');
var_dump($obj->implementsInterface('Apple'));  //Here it will checks that whether class Fruit implements interface apple or not

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keepchen2016 at gmail dot com ¶

7 years ago

interface Factory
{
    public function sayHello();
}

class ParentClass implements Factory
{
    public function sayHello()
    {
        echo "hello\n";
    }
}

class ChildrenClass extends ParentClass
{

}

$reflect = new ReflectionClass('ParentClass');
var_dump($reflect->implementsInterface('Factory'));

$second_ref = new ReflectionClass('ChildrenClass');
var_dump($second_ref->isSubclassOf('ParentClass'));

$third_ref = new ReflectionClass('Factory');
var_dump($third_ref->isInterface());

//can not be called as static
var_dump(ReflectionClass::isInterface('Factory'));
die;
//#result
bool(true)
bool(true)
bool(true)
PHP Fatal error:  Non-static method ReflectionClass::isInterface() cannot be called statically

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